Dylan weighs 45 pounds. Use the expression you derived in part I to calculate how much more Bruce weighs than Alan.

Given:  1) weight of Dylan= 45 pounds

            2) weight of Alan= 3 pounds more than twice the weight of Dylan

            3)weight of Bruce = 12 pounds less than three times the weight of

                                               Dylan.

To Find: How much more does Bruce weighs than Alan .

Solution:

weight of Dylan= 45 pounds

weight of Alan= 3 pounds more than twice the weight of Dylan

                        = 3 + ( 2×45)  pounds

                        = (3+ 90) pounds

                        = 93 pounds  

weight of Bruce= 12 pounds less than three times the weight of Dylan

                          = (3× 45) - 12  pounds

                          = (135) - 12 pounds

                          = 123 pounds

therefore, the amount by which Bruce weighs more than Alan will be given by:

weight of Bruce - weight of Alan

= 123 pounds - 93 pounds

= 30 pounds

Hence, Bruce weighs 30 pounds more than Alan.

b

step-by-step explanation:

the word superfluous means unnecessary

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3