Luci Lulu opened a cookie store in the mall. She found that the relationship between the price of a cookie, p, and the number of cookies sold, x, is given by the linear relationship x= -2000 p + 4000. Find the maximum revenue Luci can make selling cookies in one day. Find the price she should sell the cookies for to make the maximum revenue.

The maximum revenue Luci can make selling cookies in one day is $2,000.

The price she should sell the cookies to make the maximum revenue is $1

Step-by-step explanation:

W are given the following in the question:

x= -2000 p + 4000 (1)

Therefore, revenue can be obtained as follows:

Revenue = R = px = p(-2000 p + 4000) = -2000p^2 + 4000p (2)

Differentiating equation (2) with respect to p and equate to 0, we have:

dR / dp = -4000p + 4000 = 0 (3)

From equation (3), we solve for p as follows:

-4000p + 4000 = 0

4000 = 4000p

p = 4000 / 4000

p = 1

Therefore, this implies that the price she should sell the cookies to make the maximum revenue is $1.

Substituting p = 1 into (2), we have:

Revenue = (-2000 * 1^2) + (4000 * 1)

Revenue = -2000 + 4000

Revenue = 2000

Therefore, this implies that the maximum revenue Luci can make selling cookies in one day is $2,000.

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

answer4 to the second power is 16

and 4 to the third power is 64,