At the beginning of the year Monica puts a set amount of money into her health benefit account. Every month she withdraws $15 from this account for her contact lenses. After 3 months she has $255 left in her account. Write an equation in slope-intercept form to represent the relationship between the time that has passed and the amount of money left in Monica's account. Let x represent the time in months and y represent the amount of money remaining in the account.

An equation in the slope-intercept form will be:

Step-by-step explanation:

We know The slope-intercept form of the line equation

where

Let x represent the time in months

Let y represent the amount of money remaining in the account.

Given that every month Monica withdraws $15 from this account for her contact lenses

Thus, the rate of change or slope = m = 15

Given that after 3 months she has $255 left in her account.

So, we take the point (3, 255)

substituting m = 15, x = 3 and y = 255 in the slope-intercept form to determine the y-intercept

y = mx+b

255 = 15(3) + b

switch sides

15(3) + b = 255

45 + b = 255

b = 255 - 45

b = 210

Now, substituting m = 15 and b = 210 in the slope-intercept form of the line equation

y = mx+b

y = 15x+210

Therefore, an equation in the slope-intercept form will be:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.