Help me please. i need it

See explanation

Step-by-step explanation:

m∠A and m∠O are alternate interior angles so they're congruent.

m∠A = m∠O

m∠A = 65°

AM and SO are congruent sides

AM = SO

AM = 86

m∠S and m∠M are alternate interior angles so they're congruent.

m∠S = m∠M

m∠S = 60°

ON and NA are congruent sides.

ON = NA

ON = 75

m∡SNO, m∠S, and m∠O form a triangle so they should add up to 180°

m∡SNO + m∠S + m∠O = 180°

m∡SNO + 60 + 65 = 180

m∡SNO + 125 = 180

Subtract both sides by 125

m∡SNO = 55°

Hope that helped!

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

it has changed from the width and the height.

step-by-step explanation: