How many different positive four-digit integers can be created if the four digits 1, 3,5, and 6 must be used to create each integer?

You have 4 digits with which to work. The digits can be placed:

1st position: 4 possible digits

2nd position 3 possible digits

3rd position 2 possible digits

4th position 1 possible digit

Total permutations equal

4 * 3 * 2 * 1

which equals

24

Step-by-step explanation:

not sure but it may be b, as i said i'm not sure.