Please if ur good at pre calc stop to help with the first question please

Step-by-step explanation:

The first thing you ought to do is find out what you are trying to get. Desmos is an ideal program to do that if you don't have a graphing calculator. Just search for Desmos. It is pretty obvious once you get there.  I've enclosed the graph to show you what it looks like.

Notice what happens around 5.  The graph splits because effectively, you are dividing by 0 when you put 5 into the denominator. The question arises why doesn't the same thing happen at 0. It should: There is a discontinuity but it is very tiny. So the domain numbers that you should graph are

-1   0™  1   2   3   4   4.5    4.8   5.3    5.4  6 7

™I wouldn't make 0 a part of this domain.  But you can indicate with a dot where the graph goes.

I haven't filled in the range numbers. That's your job. All you have to do is fill in the table with points. Or you can put them on the graph that I have enclosed just to see where they points belong.

A graph is not to convey accuracy. It is to show the shape of function in question.

answer: i believe the answer is e

step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry