Pls answer with steps

1.) (x - 13)(x - 8)

2.) x(x - 11)(x + 13)

3.) (x - 2)(x - 4)(2x + 1)

4.) (3x + 2)(3x - 1)

5.) (x - 4)(3x + 13)

Step-by-step explanation:

1.) (x² - 13x - 9x + 117) + (x - 13)

2.) x(x² + x - 132) + x(x - 11)

= x(x + 12)(x - 11) + x(x - 11)

= x(x - 11)(x + 13)

3.) (2x³ - 12x² + 16x) + (x -2)(x -4)

= 2x(x² - 6x + 8) + (x -2)(x - 4)

= 2x(x² - 4x - 2x + 8) + (x -2)(x -4)

4.) 9x² - 4 + (3x + 2)

= (3x)² -2² + (3x + 2)

= (3x + 2)(3x - 2) + (3x + 2)

5.) (3x² - 48) + (x - 4)

= 3(x - 4)(x + 4) + (x - 4)

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: