Find the missing side lengths . Leave your answers as radicals in simplest form. Does anybody knows how to do it cause I don’t so can y’all plz help me

Step-by-step explanation:

Question 9:

Hypotenuse = 7

Leg = Hypotenuse / √2 = 7/√2 = 7√2 / 2.

Therefore x = y = 7√2 / 2.

Question 10:

Leg = 10

Since x is also a Leg, x = 10.

Hypotenuse = Leg * √2 = 10√2. => y = 10√2.

Question 11:

Leg = 7

Since x is also a Leg, x = 7.

Hypotenuse = Leg * √2 = 7√2, => y = 7√2.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )