What is the equation for a line with slope -4 and y-intercept 1?

Step-by-step explanation:

General line equation: y = mx + c, where

m is the line slope and c is the y-intercept.

Hence our line equation is y = -4x + 1.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)