Please help this is due today

Show work please

↓↓↓Btw sorry its not in order

Step-by-step explanation:

m∠62 and ∠g are vertical angles so they're congruent.

∠g = 62°

∠f and m∠62 are linear pairs so they're supplementary

∠f + 62 = 180

∠f = 118°

∠e is a right angle and is supplementary to a 90° angle

∠e = 90°

Adding ∠e, m∠28° and the missing angle should sum up to 180° since its a triangle. x = missing angle

x + ∠e + m∠28 = 180°

x + 90 + 28 = 180

x + 118 = 180

x = 62°

∠h ≅ x

∠h ≅ 62

∠h = 62°

∠b and m∠28 are vertical angles so they're congruent.

∠b ≅ m∠28

∠b = 28°

∠b and ∠a are linear pairs so they are supplementary.

∠a + ∠b = 180

∠a + 28 = 180

∠a = 152°

∠c and ∠a are corresponding angles so they're congruent.

∠c ≅ ∠a

∠c ≅ 152

∠c = 152°

∠c and ∠j are vertical angles so they're congruent.

∠j ≅ ∠c

∠j ≅ 152

∠j = 152°

The corresponding angle of c is 152° as well. Let's call it y. Y corresponds to the angle with a bisector. Call that whole angle z.

z ≅ y

z ≅ 152

z = 152°

Z has a bisector meaning the two angles that formed because of the bisector are congruent.

∠d and the other angle add up to 152°. They're equal.

∠d = 152 ÷ 2

∠d = 76°

Hope I helped!

the answer is 45 i just did it on oddesy ware

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step-by-step explanation:

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