Determine the center and radius of the following circle equation: x^2+y^2-14x+4y+52=0 x 2 +y 2 −14x+4y+52=0

Step-by-step explanation:

x² + y² - 14x + 4y + 52 = 0

(x - 7)² - 49 + (y + 2)² - 4 + 52 = 0

(x - 7)² + (y + 2)² = 1

Hence the circle's center is (7, -2) and the radius is 1.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116