A monkey is swinging from a tree. On each swing she travels along an arc that is 75% as long as the previous swing arc. The total length of the arcs from her first 4 swings is 175m.

The first swing is 64m

Step-by-step explanation:

The complete question asks for how long the first swing is.

The monkey is swinging from the tree with each swing being along an arc, where each arc is 75% of the previous arc. Also, given that its first four swings is 175cm, we can denote her first swing as y.

This means the second swing would be = 0.75y

The third would be = 0.75(0.75y) = 0.5625y

The fourth would be = 0.75(0.5625y) = 0.421875y

Since the total is 175, we have

y + 0.75y + 0.5625y + 0.421875y = 175

2.734375y = 175

y = 175/2.734375

y = 64m

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)