Y=-x^2-12x-37 find the 1) Roots 2) Factors 3) Vertex (x, y) 4) Interception with 'Y" axis 5) Axis of Symmetry 6)Direction of Opening 7)Max / Min ? Coordinates 8)Sketch 9) Domain 10) Range

1) The roots of the equation Y = -x² - 12·x - 37 are x = -6 - √73 and -6 + √73

2) The factors of the function Y = -x² - 12·x - 37 are (x + (-6 - √73)) and (x - (-6 + √73))

3) The vertex is (-6, -1)

4) The Y-intercept is (0, -37)

5) The axis of symmetry is x = -6

6) The parabola opens downward

7) The maximum point is (-6, -1)

8) The graph of the function created with Microsoft Excel is attached

9) The domain of the function is -∞ < x < ∞

10) The range of the function is -∞ < Y ≤ -1

Step-by-step explanation:

The given function is Y = -x² - 12·x - 37

1) The roots of the equation Y = -x² - 12·x - 37 is given as follows;

0 = -x² - 12·x - 37

∴ -x² - 12·x - 37 = 0

The roots are;

x = (12 ± √((-12)² - 4 × 1 × (-37)))/(-2)

∴ x = -6 - √73 and -6 + √73

2) The factors are (x + (-6 - √73)) and (x - (-6 + √73))

3) The vertex is given by h = -b/(2·a) = 12/(2) = -6

k = c - b²/(4·a) = -37 - 144/(-4) = -1

The vertex = (h, k) = (-6, -1)

4) The intercept with the "Y" axis is given when x = 0, therefore, the y-intercept is (0, -37)

5) The axis of symmetry can be found at the vertex or the line x = -6

6) The sign of the coefficient of x² is negative therefore, the parabola opens downward

7) The maximum point is given as follows;

At the maximum point, dY/dx = d(-x² - 12·x - 37)/dx = -2·x - 12 = 0

x = 12/(-2) = -6, which is the vertex, therefore Y = -(-6)² - 12×(-6) - 37 = -1

The maximum point is the vertex (-6, -1)

8) Please find attached the graph of the function created with Microsoft Excel

9) The domain of the function is -∞ < x < ∞

10) The range of the function is -∞ < Y ≤ -1

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: