A committee must be formed with 4 teachers and 5 students. If there are 7 teachers to choose from, and 15 students, how many different ways could the committee be made?

Step-by-step explanation:

There are a total of 10 persons (6 teachers + 4 students) from which a committee of 5 is to be formed. This can be done in 10C5 ways.

The number of ways that a committee can be formed with no students in it is to select 5 teachers out of the pool of 6 teachers available. This can be done in 6C5 ways.

Therefore the total number of ways that the committee can be formed with at least one student in it is 10C5 - 6C5.

10C5 = 252

6C5 = 6

Therefore the required number of ways = 246

8121 because

130,000 divided by 16 is 8121

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are