A point K is on the perpendicular bisector of a segment with endpoints at H and J. What must be true about point K? It is equidistant from H and J It falls on the h j It is at the midpoint of h j Not enough information is given

is equidistant from and .

Step-by-step explanation:

Given that the point which is on the perpendicular bisector of the line segment having endpoints at and .

The given situation can be represented as the diagram as attached in the answer area.

Referring to the :

(As it is the perpendicular bisector)

(As it is the perpendicular bisector)

Also, the side is the common side.

Therefore by congruence,

As per the properties of congruent triangles:

Side = Side

and are nothing but the distance of the point from the end points and which are proved to be equal to each other.

Therefore, we can conclude that:

is equidistant from and .

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0