Find the 62nd term of the following sequence:
(-21, – 27, - 33, - 39,...)

-387

Step-by-step explanation:

First term (T1) = -21 = a

second term (t2) = - 27

common difference (d) = t2 - t1 = - 27 + 21 = - 6

Now

Tn = a + ( n - 1) d

T62 = - 21 + ( 62 - 1 ) - 6

= - 21 -366

= -387

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

where is the figure