What resistance would produce 125 amps from a 6.0 volt battery

0. 048

Step-by-step explanation:

Given that V=IR

R=V/I

R=6.0/125

R=0. 048ohms

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong