A powerful computer is purchased for $2500, but loses 18% of its value each year. How much will it be worth 4 years from now?

$1130.30

Step-by-step explanation:

Step one:

given data

cost of computer=  $2500

rate of loss per year= 18%

time t= 4 years

Step two:

let us computer the loss per year

Year 1 loss

worth= 2500- 2500*0.18

worth= 2500-450

worth= $2050

Year 2 loss

worth= 2050- 2050*0.18

worth= 2050-369

worth= $1681

Year 3 loss

worth= 1681-  1681*0.18

worth= 1681-302.58

worth= $1378.42

Year 4 loss

worth= 1378.42-  1378.42*0.18

worth= 1378.42-248.1156

worth= $1130.30

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

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