Does the graph in Exercise 33 have a Hamilton path? If so, find such a path. If it does not, give an argument to

show why no such path exist

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there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

yo answer should be 6 if im not mistaken

step-by-step explanation: