herlene has 5.05 in quarters and dimes. The number of quarters is one more than twice the number of dimes. Find the number she has of each kind.

Herlene has 8 dimes and 17 quarters

Step-by-step explanation:

System of Equations

Let's call:

x = number of dimes Herlene has

y = number of quarters Herlene has

Since each dime has a value of $0.10 and each quarter has a value of $0.25, the total money Herlene has is 0.10x+0.25y.

We know this amount is $5.05, thus:

0.10x + 0.25y = 5.05        [1]

It's also given the number of quarters is one more than twice the number of dimes, i.e.:

y = 2x + 1        [2]

Substituting in [1]:

0.10x + 0.25(2x + 1) = 5.05

Operating:

0.10x + 0.5x + 0.25 = 5.05

0.6x = 5.05 - 0.25

0.6x = 4.8

x = 8

From [2]:

y = 2*8 + 1 = 17

y = 17

Herlene has 8 dimes and 17 quarters

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.