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Mathematics, 07.01.2021 22:30 trvptierra
In ΔIJK, \overline{IK}
IK
is extended through point K to point L, \text{m}\angle JKL = (5x-3)^{\circ}m∠JKL=(5x−3)
∘
, \text{m}\angle KIJ = (2x+8)^{\circ}m∠KIJ=(2x+8)
∘
, and \text{m}\angle IJK = (x-1)^{\circ}m∠IJK=(x−1)
∘
. Find \text{m}\angle JKL. m∠JKL.
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Answers: 3
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You know the right answer?
In ΔIJK, \overline{IK}
IK
is extended through point K to point L, \text{m}\angle JKL = (5x-3)...
is extended through point K to point L, \text{m}\angle JKL = (5x-3)...
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