Hooke’s Law of Elasticity states that the force applied, y, varies directly with the distance a spring stretches, x (assuming the spring is not stretched past its elastic limit). If a force of 160 newtons stretches a spring 800 cm, how far will a force of 368 newtons stretch the same spring? Justify your answer. Group of answer choices

F. It will stretch the same spring 73.6 cm because the equation is y equals 5x.

G. It will stretch the same spring 73.6 cm because the equation is y equals one fifth x..

H. It will stretch the same spring 1,840 cm because the equation is y equals 5x.

J. It will stretch the same spring 1,840 cm because the equation is y equals one fifth x..

H:  It will stretch the same spring 1,840 cm because the equation is y equals 5x.

Step-by-step explanation:

800=y

160and368=x

You find the answer by dividing,

800 divided by 160 equals 5 which means the equation is y equals 5x

and 368x5=1,840

also, do you go to college park?

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15