17 apples and 12 oranges cost $10.44. 3 apples and 4 oranges cost $2.84. How much does 1 orange cost?

0.48$

Step-by-step explanation:

Cost of 1 Apple = A

Cost of 1 Orange = O

Six apples and three oranges cost $3.36 equivalent to:

6A + 3O = 3.36 (1st equation).

Two apples and five oranges cost $3.04 equivalent to:

2A + 5O = 3.04 (2nd equation).

Now we have to solve the 2 equations with 2 uknowns (the cost of 1 Apple = A, and the cost of 1 Orange = O).

6A + 3O = 3.36 (Equation 1)

2A + 5O = 3.04 (Equation 2), multiplying this equation by 3 we get:

6A + 3O = 3.36 (Equation 1)

6A + 15O = 9.12 (Equation 2), Now equation 2 minus equation 1 we get:

6A-6A +15O -3O = 9.12-3.36 equivalent to:

12O = 5.76 => O = 5.76/12 = 0.48 ( the cost of one Orange is 0.48$)

Go back to equation 1 and solve for the cost of 1 apple:

6A + 3x0.48 = 3.36 =>

6A + 1.44 = 3.36 =>

6A = 1.92 =>

A = 1.92/6 = 0.32 ( the cost of one apple is 0.32$)

Summary: The cost of one apple is 0.32$ and the cost of one orange is 0.48$.

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.