1.) Given : S is the midpoint of RT; PR = PT Prove : PRS = PTS

2.) Given : E is the midpoint of AB and CD

Prove: AEC=BED

1.

Given: S is the midpoint of RT

PR=PT

To Prove: PRS=PTS

Step-by-step explanation:

If PR=PT in a triangle PRT, then the triangle is isosceles triangle.

Therefore,  ∠PRT=∠PTR (opposite angles of an isosceles triangle are equal)

In ▲PRS and ▲PTS

PR=PT

∠PRT=∠PTR

PS=PS (PS is common)

therefore, ▲PRS≅▲PTS

Therefore, ∠PRS=∠PTS

Hence proved.

2.

Given: E is the midpoint of AB and CD.

To Prove: AEC=BED

Step-by-step explanation:

If AB and CD are the diagonals of rectangle, then

diagonals AB=CD,  sides AC=BD and AD=BC

In ▲AEC and ▲BED,

∠AEC=∠BED(vertically opposite angles)

AE=BE

AC=BD

therefore, ▲AEC≅▲BED

Therefore,  ∠AEC=∠BED

Hence Proved.

answer: options?

step-by-step explanation: