There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus five. What is the first integer described? Will give Brainliest

3

Step-by-step explanation:

Given that:

Integers : x, x + 1, x + 2

6x - 2(x + 1) = (x+2) + 5

6x - 2x - 2 = x + 2 + 5

4x - 2 = x + 7

4x - x = 7 + 2

3x = 9

x = 9/3

x = 3

First integer = x = 3

2nd integer = x + 1 = 3+1 = 4

3rd Integer = x + 1 + 1 = 3 + 2 = 5