A line passes through the point (-10, -6) and has a slope of 1/2 . Write an equation in slope-intercept form for this line.

Step-by-step explanation:

formula for slope-intercept is [ y= mx + b  ]

we are given a point P=(x1,y1) = (-10,-6)

and a slope m of 1/2

use the point slope formula [ y-y1 = m(x-x1) ]  with the given info then work it into the slope-intercept form

y-(-6) = 1/2(x-(-10))

y+6 = 1/2(x+10)

y+6 = 1/2x+5

y= 1/2x + 5-6

y=1/2x-1

this looks like the point-slope form so you are done  :)  

move it to the other side

step-by-step explanation: