Equation C: a = 4b + 5 Equation D: a = 6b − 2 What value of a can be substituted into equation D to solve the system of equations? 4b + 5 6b − 2 4b 6b

The value of a that can substituted into equation D = 4b + 5

Step-by-step explanation:

Given that:

a = 4b + 5   (equation c)

a = 6b - 2   (equation d)

Replace the value of a = 4b + 5 into "a" in (equation d) to solve the system of equations.

So;

4b + 5 = 6b -2

5 + 2 = 6b -4b

7 = 2b

b = 7/2

b = 3.5