Triangle A has a side lengths of 3,4, and 5 Triange B has side lengths of 6,7,and 8 give possible side lengths so triangle B os similar to triangle A

A. Given that ∆A has side lengths 3, 4, and 5, that corresponds to the side lengths 6, 7, and 8 of ∆B, both ∆s can only be similar to each other if the ratios of their corresponding side lengths are equal.

Thus:

≠  ≠  .

✅The ratio of their corresponding side lengths is not equal, therefore, triangle B is not similar to triangle A.

B. To get the possible side lengths for triangle B to make it similar to triangle A, simply multiply each side length of triangle A by a scale factor.

Let's use a scale factor of 2.

3 × 2 = 6

4 × 2 = 8

5 × 2 = 10.

✅Possible side lengths for triangle B that will make it similar to triangle A are: 6, 8, and 10.

Step-by-step explanation:

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hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

did u ever get the answers? i need