Mr. Sanders teaches a painting class. He makes the histogram below to summarize the number of paintings each student has completed since the class began. Mr. Sanders says that the histogram shows that 1/3 of the students have finished 12 or more paintings.

Mr Sanders likely found that 1/3 of students have completed 12 or more paintings because there are 6 bars on the histogram, and 2 of the bars represent students with 12 or more completed paintings. The actual fraction of the students who have completed 12 or more paintings is 4/19.

Step-by-step explanation:

There are 19 students in Mr Sanders's class. There are 6 bars on that histogram. He most likely thought that since the 2/6 is equal to 1/3, 1/3 of his students completed 12 or more paintings. That is not the case. Two-sixths/one-third isn't even a whole number. The other options are 2/3, 4/19, and 4/17. Two-thirds and four-seventeenths are not whole numbers as well. So that leaves 4/19. Four-nineteenths is actually equal to the whole number 4. We must put 4/19 as our answer because there are no such things as partial students...

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

what level of math? also i don't need to be paid if i can you.