The sandwich shop has 6 employees, but only 3 people need to work at any one time. The manager wants to have a different group of people work together every day for two weeks. Is that possible?

Yes

Step-by-step explanation:

Given that:

Number of employees (n) = 6

Number of employees who can work at a time (r) = 3

To know of its possible for different groups of employees to work for two wweka, then, the number of different groups or combination must be greater Than or equal to 14 (two weeks) ; Assume (1 week = 14 days)

Using the combination formula :

nCr = n! ÷ (n - r)!r!

6C3 = 6! ÷ (6 - 3)!3!

6C3 = 6! ÷ 3!3!

6C3 = (6*5*4) ÷ (3*2*1)

6C3 = 120 / 6

6C3 = 20 ways

Hence, 20 different groups of 3 employees can be made from all 6 employees. Hence, it is possible to have different groups work for two weeks

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

related questions

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :