A car start from rest and accelerates at the rate of 2ms² for 5 seconds. it maintenance this velocity for another 5 seconds. it eventually undergoes a uniform deceleration and finally comes to rest after further 5 seconds. A) draw the velocity-time graph for the journey B) find the acceleration and deceleration respectively,

C) find the total distance travelled during each stage.

D) find the average velocity over the entire period

Acceleration = 2m/s ; deceleration = - 2 m/s

Distance covered :

Stage 1 = 25

Stage 2 = 50 m

Stage 3 = 25m

Average Velocity = 6.67 m/s

Step-by-step explanation:

Given that:

Acceleration = 2m/s

Final velocity, v

v = u + at

u = 0 (from rest)

v = 0 + 2(5)

v = 10 m/s

deceleration ;

Final velocity, v ;

v = u + at

v = 0 ( to rest)

0 = 10 + a * 5

0 = 10 + 5a

-5a = 10

a = 10 / - 5

a = - 2 m/s^2

Distance traveled during each stage :

Distance = speed * time

Stage1 = S = 0.5at^2 = 0.5 * 2 * 5^2 = 0.5 * 2 * 25 = 25 meters

Stage 2 = Distance = speed * time = 10m/s * 5 = 50 metres

Stage 3 = distance = S = 0.5at^2 = 0.5 * 2 * 5^2 = 0.5 * 2 * 25 = 25 meters

Average Velocity :

Total distance traveled / total time taken

(25 + 50 + 25)m / 15s

100m / 15 s

Average Velocity = 6.667 m/s

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

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substitute the values

the measure of angle xoy is equal to

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substitute the value

don't report but were is the digram

step-by-step explanation: