the zero of the quadratic polynomial x^2+99x+127 are a both positive b both negative c one +ve one-ve d both equal. please help

Step-by-step explanation:

By Descrates' Rule of Signs,

x² + 99x + 127 changes sign 0 times.

Hence it has 0 positive roots.

Since the discriminant b² - 4ac is also positive, there are 2 real distinct roots.

Hence both the roots are negative. (B)

6/20

step-by-step explanation:

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.