The Population of a town was 12000 in 1980 and 16000 in 1990.
What was the percent increase in
the population of the town during
this period?
[2011]

33.3%

Step-by-step explanation:

Step one:

given data

Initial population (1980)= 12000

Final population(1990)= 16000

change in population= 16000-12000= 4000

Step two:

% increase= change in population/initail population *100

%increase= 4000/12000*100

%increase= 0.333*100

% increase= 33.3%

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.