How does the idea of a reference triangle allow us to extend right triangle trigonometry to angles greater than 90 degrees?

15.36 per mile

but forgot to round

i am pretty sure

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

1,2,4,5,10,11,20,22,44,55,110,220