Is this the X factor method and how would you do it?

Work Shown:

4x^2 - 8x - 192

4(x^2 - 2x - 48)

4(x - 8)(x + 6)

We see that (x - 8) is one factor

To factor x^2-2x-48 into (x-8)(x+6), we need to find two numbers that

Through trial and error you should find the two values are -8 and 6 since

Another approach is to use the quadratic formula to solve x^2-2x-48 = 0. You should find that the two roots are x = 8 and x = -6.

Those two roots lead to the equations x-8 = 0 and x+6 = 0.

Then use the zero product property to get (x-8)(x+6) = 0

This shows that x^2-2x-48 factors to (x-8)(x+6)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2