If J is the centroid of CDE, DE=52, FC=15, and HE= 14, find each missing measure

DG = 26, GE = 26, DF = 15, CH = 14, CE = 28

IF If J is the  centroid of CDE, this means that J divides CG, FE, DC, CE and DH into two equal parts

Therefore,

DG + GE = DE ....(1)

DG = GE ...(2)

Substituting (2) in (1) ,we get

DG + DG = DE

2DG = DE

Also, DE = 52  (Given)

So, 2DG = 52

DG = 26

As, DG = GE,

Therefore,  GE = 26

Also,  DF + FC = DC and DF = FC

As, FC = 15,

So, DF = 15

Also CH + HE = CE and CH = HE

Since HE = 14,

So, CH = 14

CE = 14+14=28

So, CE = 28

Therefore, DG = 26 , GE = 26, DF = 15, CH = 14, CE = 28

Learn more:link

DG = 26

GE = 26

DF = 15

CH = 14

CE = 28

Step-by-step explanation:

Find the image attached for the complete question

IF If J is the centroid of CDE, this means that J divides CG, FE, DC, CE and DH into two equal parts.

The following expressions are therefore true

DG + GE = DE and DG = GE

Substituting

DG + DG = DE

2DG = DE

Given DE - 52

2DG = 52

DG = 52/2

DG = 26

Since DG = GE, hence GE = 26

Also DF + FC = DC and DF = FC

Since FC = 15, hence DF = 15

Also CH + HE = CE and CH = HE

Since HE = 14, hence CH = 14

CE = 14+14

CE = 28

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!