The points (-5, -22) and (4, r) lie on a line with slope 3. Find the missing coordinate r.

Step-by-step explanation:

here,

x1= -5. x2=4

y1= -22. y2=r

slope(m)=3

now we have,

m=(y2-y1)/(x2-x1)

or,3=(r-(-22))/(4-(-5))

or,3=(r+22)/(4+5)

or,3=(r+22)/9

or,27=r+22

or,r=27-22

or,r=5

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.