How many years, to the nearest tenth, will be needed for $5000 to increase to $18000 at 3.0% annual interest compounded

Complete question :

How many years, to the nearest tenth, will be needed for $5000 to increase to $18000 at 3.0% annual interest compounded monthly

Step-by-step explanation:

Initial amount (P) = 5000

Final amount (A) = 18000

Interest rate (r) = 3% = 0.03 compounded monthly

A = P(1 + r/n)^nt

n = number of compounding timea per period

18000 = 5000(1 + 0.03 / 12)^12t

18000 / 5000 = (1 + 0.0025)^12t

3.6 = (1 + 0.0025)^12t

3.6 = 1.0025^12t

Take the In of both sides

1.2809338 = 1.03t

t = 1.2809338 / 1.03

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!