30. Find the equation of straight line whose slope is 3 times and y-intercept is double of the line
2x - 3y = 4.

Step-by-step explanation:

gradient/slope = 3

y-intercept

2x - 3y = 4

3y = 2x - 4

y = 2/3x - 4/3

so y-intercept is double -4/3 so... -4/3x2 = -8/3

the equation of the line is

y = 3x - 8/3 or 9x - 3y = 8

3y=2x-8

Step-by-step explanation:

when y intercept x=0

2(0)-3y=4

-3y=4

y=-4/3

when x intercept y=0

2x -3(0)=4

2x =4

x=2

point (2,-4/3)

gradient

-3y=-2x +4

y=2x/3-4/3

gradient=2/3

equation

y+4/3=2/3(x-2)

3y+4=2x-4

3y=2x-8

the answer is 45 i just did it on oddesy ware

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2