Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.48089 7,805.62898 6,423.16445

Step-by-step explanation:

The nth term of a geometric progression can be determined by using the formula:

Tn=arn−1

where: a = first term and r = common ratio

Substitute the given values of first term and common ratio into the formula:

Tn=arn−1

T5=(40)(0.5)5−1

T5=(40)(0.5)4

T5=(40)(0.0625)

T5=2.5

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8