Consider the graph below. 10px
4
2
-10
-4
-2
8
10
0 2
4
What is the equation of the line in slope-intercept form?
A y=x+8
By=2 - 8
y = 8x + 8
Dy = 8x - 8

B. y = x - 8

Step-by-step explanation:

✔️First, find the slope of the line using two points on the line, say (0, -8) and (8, 0):

slope (m) = 1

✔️Find the y-intercept (b):

The y-intercept is -8. The line intercepts the y-axis at y = -8.

b = -8

✔️Next, substitute m = 1, and b = -8 into y = mx + b:

Thus:

y = (1)x + (-8)

y = x - 8

a

step-by-step explanation:

a

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐