This question is worth 100 points please answer now. Algebra 2. I will mark you brainliest. Show all work to identify the asymptotes and zero of the function f of x equals 4 x over quantity x squared minus 16.

The vertical asymptotes occur at x = 4 and x = -4

The zero of the function is (0, 0)

Step-by-step explanation:

The given function is

Therefore, we have;

The asymptote is given at the value of x for which the denominator = 0, therefore, the asymptote are the values of x that make the denominator of the equation equal to zero, which are given as follows

For the asymptote, the denominator = x² - 16 = (x - 4)·(x + 4) = 0

Therefore, the vertical asymptotes are the lines x = 4 and x = -4.

The zero of the function is given as follows;

Therefore, 4·x = (x - 4)·(x + 4) × 0 = 0

x = 0/4 = 0

Therefore, when f(x) = 0, x = 0 and the zero of the function = (0, 0).

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz