Find five consecutive integers whose sum is 195

To do this, come up with three numbers. These are n, n+1, n+2, n+3, and n+4.

To solve, you do this:



Then, substitute 37 into the numbers:

n=37
n+1=37+1=38
n+2=37+2=39
n+3=37+3=40
n+4=37+4=41

The five consecutive integers are 37, 38, 39, 40, and 41.