Triangle A is reflected in the x axis to give triangle B, which is then reflected in the line y=x to give Triangle C. Draw Triangle C.

The coordinates of triangle C are  (-5,4) , (-2,2) and (-2,4)

From the given image the vertices of the triangles are

Triangle A has coordinates (4,5) , (2,2) and (4,2)

After reflecting triangle A in the x-axis, triangle B is obtained  

On reflection in x-axis, the x-axis coordinates remain same while the y-axis coordinates become negative with the same magnitude.

Hence, the coordinates of triangle B are (4,-5),(2,-2) and (4,-2)

Now as triangle B is reflected by the line y = x to get triangle C,  the x and y coordinates of triangle B are interchanged.

So, the coordinates of triangle C are (-5,4),(-2,2) and (-2,4)

Learn more about transformation by reflection on axis:

link

The coordinates of triangle C on the grid are

(-5,4) , (-2,2) and (-2,4)

Step-by-step explanation:

We can identify the coordinates of the vertices of the triangles so as to get a diagram

For the first triangle, we have the following coordinates;

(4,5) , (2,2) and (4,2)

Now, let us get the coordinates of triangle B after reflecting triangle A in the x-axis

what we have in this case is that the x-axis coordinates stays same while the y-axis values are negated

Hence, the coordinates of triangle B are;

(4,-5) , (2,-2) and (4,-2)

Lastly we are to reflect triangle B in the line y = x so we get triangle C

A reflection over the line y= x means that we are going to switch the place of the x and y coordinates of the pre-image

So, the coordinates of triangle C are;

(-5,4) , (-2,2) and (-2,4)

answer: e 9, 5.75

step-by-step explanation:

step 1

find the variation ab in the x coordinate

delta x=(x2-x1)=10-> 8 units

find the variation ab  in the y coordinate 

delta y=(y2-y1)=6-> 2 units

step 2

find the coordinates point c

  x coordinate 

cx=ax+delta x*2/> cx=2+8*(2/> cx=3

  y coordinate 

cy=ay+delta y*2/> cy=4+2*(2/> cy=4.25

the coordinates of point c are (3,4.25)

step 3

find the coordinates point d

  x  coordinate 

dx=ax+delta x*4/> dx=2+8*(4/> dx=4

  y  coordinate 

dy=ay+delta y*4/> dy=4+2*(4/> dy=4.5

the coordinates of point d are (4, 4.5)

step 4

find the coordinates point e

  x  coordinate 

ex=ax+delta x*4/> ex=2+8*(6/> ex=5

  y  coordinate 

ey=ay+delta y*4/> ey=4+2*(6/> ey=4.75

the coordinates of point e are (5, 4.75)

step 5

find the coordinates point f

  x  coordinate 

fx=ax+delta x*4/> fx=2+8*(8/> fx=6

  y  coordinate 

fy=ay+delta y*4/> fy=4+2*(8/> fy=5

the coordinates of point f are (6,5)

step 6

find the coordinates point g

  x  coordinate 

gx=ax+delta x*4/> gx=2+8*(10/> gx=7

  y  coordinate 

gy=ay+delta y*4/> gy=4+2*(10/> gy=5.25

the coordinates of point g are (7,5.25)

step 7

find the coordinates point h

  x  coordinate 

hx=ax+delta x*4/> hx=2+8*(12/> hx=8

  y  coordinate 

hy=ay+delta y*4/> hy=4+2*(12/> hy=5.5

the coordinates of point h are (8,5.5)

step 8

find the coordinates point i

  x  coordinate 

ix=ax+delta x*4/> ix=2+8*(14/> ix=9

  y  coordinate 

iy=ay+delta y*4/> iy=4+2*(14/> iy=5.75

the coordinates of point i are (9,5.75)

- r3ktforgood ☕