What's the results for √(-4--3)²+(3-2)² , i found 2 but i think it's false

I think that you are right (-4--3=-4+3=-1)-1 squared is 1 and the square root of 1  (3-2=1) 1 squared is 1 so 1+1=2 (PEMDA)

√(-4-(-3)^2+(3-2)^2 √(-4+3)^2+(3-2)^2 √(-1)^2+(1)^2 √1+1 Final √2 or 1.414

Ithink the answer is $2.10