If 16 horses eat 5 stacks of hay in 35 days, how many horses can eat 4 stacks of hay in 8 days? Math question

The number of horses that can eat 4 stacks of hay in 8 days = 56 horses

Step-by-step explanation:

The given parameters are;

The time it takes 16 horses to eat 5 stacks = 35 days

Therefore;

The time it takes 16 horses to eat 5/5 stacks (1 stack) = 35 days/5 = 7 days

The time it takes 16 horses to eat 1 stack of hay = 7 days

The time it takes 16 horses/16 to eat 1 stack of hay = 7 days × 16 = 112 days

Therefore;

The time it takes 1 horse to eat 1 stack of hay = 112 days

The time it takes 1 horse to eat 4 × 1 stack of hay = 112 days × 4 = 448 days

The time it takes 1 horse to eat 4 stacks of hay = 448 days

Therefore, given that (448 days)/(8 days/horse) = 56 horse, we have;

The number of horses that will eat 4 stacks of hay in 8 days = 56 horses.

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

a

step-by-step explanation:

given the 2 equations

- x + y = - 2 → (1)

2x - 3y = 4 → (2)

multiplying (1) by 2 and adding to (2) will eliminate the x- term

- 2x + 2y = - 4 → (3)

add (2) and (3) term by term

(2x - 2x) + (- 3y + 2y) = (4 - 4), simplifying gives

- y = 0 ⇒ y = 0

substitute y = 0 in either of the 2 equations for corresponding value of x

substituting in (2) gives

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 0 ) → a