the letters of the word independent are written on individual card and the cards are put into a box a card is selected and then replaced and then a second card is selected find the probality of obtaining the letter p twice

The probability of obtaining the letter p twice is 1/121

Step-by-step explanation:

Probability of Recurring Events

There are 11 letters in the word 'independent', one of which is the letter 'p'.

When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.

This means the individual probability of getting a 'p' is:

The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:

We'll use the multiplication rule. Just multiply the probability of the first event by the second.

The probability of obtaining the letter p twice is 1/121

i dont know

step-by-step explanation:

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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