Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-4, -2)A(−4,−2)A, left parenthesis, minus, 4, comma, minus, 2, right parenthesis, B(-2, -2)B(−2,−2)B, left parenthesis, minus, 2, comma, minus, 2, right parenthesis, C(-2, 7)C(−2,7)C, left parenthesis, minus, 2, comma, 7, right parenthesis, and D(-4, 7)D(−4,7)D, left parenthesis, minus, 4, comma, 7, right parenthesis.
What is the area of rectangle ABCDABCDA, B, C, D?
square units

The  area of the rectangle is given by the product of length and the

width of the rectangle.

Response:

The coordinates of the vertices of rectangle ABCD are;

A(-4, -2), B(-2, -2), C(-2, 7), and D(-4, 7)

Required:

The area of rectangle ABCD

Solution:

The distance between sides that have the same x or y coordinates are

given by the difference between the other coordinates, as follows;

Length of AB = -2 - (-4) = 2

Length of BC = 7 - (-2) = 9

Length of CD = -2 - (-4) = 2

Length of AD = 7 - (-2) = 9

Therefore;

Length of the rectangle = 9 units

Width of the rectangle = 2 units

The area of a rectangle = Length × Width

The area, A, of the rectangle is therefore;

A = 9 units × 2 units = 18 units²

Learn more about the area of geometric shapes here:

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answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

unless if u could do my questions, if not i wouldn't want to