Write the equation in standard form of the line that passes through the points (7,-3) and (-3,1).

y-intercept form of that equation:

y=-2/5x+b

1=-2/5(-3)+b

1=6/5+b

b=-1/5

y=-2/5x-1/5

standard form:

2/5x+y=-1/5

srry im too busy rn so i couldnt explain very well :/

Step-by-step explanation:

Standard Form: 4/10x + y = -0.2

Step-by-step explanation:

(7,-3) and (-3,1)

m = y2 - y1/x2 - x1

m = 1 - (-3)/-3 - 7

m = 1 + 3/-10

m = -4/10

y - y1 = m(x - x1)

y - 1 = -4/10(x + 3)

y - 1 = -4/10x - 1.2

y = -4/10x - 1.2 + 1

y = -4/10x - 0.2

Standard form: Ax + By = C

y = -4/10x - 0.2

4/10x + y = -0.2

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this