A rectangular room is 3 meters wide, 4 meters long and 2 meters high. How far is it from the northeast corner at the floor to the southwest corner at the ceiling

5.385

Step-by-step explanation:

We are given that the room is 3 meters in length, 4 meters in width, and a height of 2 meters.

To start with, we would need to use the Pythagorean Theorem to get the diagonal length of the box floor. The height doesn't matter here, at least not yet.

Using Pythagoras and considering the width and length, we have

3² + 4² = c²

9 + 16 = c²

25 = c²

c = 5

This is the diagonal length of the floor. Again, we create a whole new triangle making use of the height, the diagonal of the floor, and the distance we need. So we have

5² + 2² = c²

25 + 4 = c²

29 = c²

c = √29

c = 5.385 m

Thus, the needed distance is 5.385 m

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)